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Jan 29, 2022 at 18:37 comment added spiridon_the_sun_rotator one needs to specify for convexity with respect to which variable the function is. I spoke about convexity with respect to the input arguments of the loss function. $\mathrm{MSE} = \frac{1}{2}(y - \hat{y})^2$ is convex with respect to the prediction $y$. But if you are speaking about convexity with respect to the NN weights, the resulting function generally will be non-convex.
Jan 29, 2022 at 16:54 comment added Edoardo Guerriero Convex in their formulation, but when applied in neural networks they lose this property, for details check this thread math.stackexchange.com/questions/2402455/…
Jan 29, 2022 at 6:21 comment added spiridon_the_sun_rotator I would disagree, that every loss function is non-convex. Mean squared error and Crossentropy (Binary or Multilabel) are convex functions.
Jan 28, 2022 at 16:23 history edited Edoardo Guerriero CC BY-SA 4.0
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Jan 28, 2022 at 16:18 history undeleted Edoardo Guerriero
Jan 28, 2022 at 16:08 history deleted Edoardo Guerriero via Vote
Jan 28, 2022 at 16:05 history answered Edoardo Guerriero CC BY-SA 4.0