Timeline for How the vector-space isomorphism between $\mathbb{R}^{m \times n}$ and $\mathbb{R}^{mn}$ guarantees reshaping matrices to vectors?
Current License: CC BY-SA 4.0
4 events
| when toggle format | what | by | license | comment | |
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| May 28, 2023 at 21:52 | comment | added | David | @Eponymous "the author is teaching maths, not engineering" absolute savage hahahaha | |
| Sep 30, 2022 at 18:15 | comment | added | PeaBrane | @Eponymous Both of them describes a vector space of dimension $nm$. In this case, multiple automorphisms exist for this object, two of which you gave as example. An automorphism always exists for any object (the identity mapping), and that is what the OP wanted to show. | |
| Sep 30, 2022 at 15:25 | comment | added | Eponymous | $\mathbb{R}^{n\times m}$ and $\mathbb{R}^{nm}$ are different spaces: matrices and vectors. Each real value in a matrix has a row and a column. Each value in a vector has just an index. There are two standard mappings between them: row-major and column-major, plus many uncommon mappings. Therefore they are not "the same" space (although they are isomorphic.) You must specify which mapping you want to use before moving between them. The author is teaching math, not engineering, and therefore must make this distinction. | |
| Aug 31, 2022 at 8:16 | history | answered | PeaBrane | CC BY-SA 4.0 |