By definition of $V_{n+1}$, we have:
$V_{n+1} = \frac{\sum_{k=1}^{n} W_{k} G_{k}}{\sum_{k=1}^{n} W_{k}} \; \tag{1}$
Then, taking the $n^{th}$ term out of the sum in the numerator, we have:
$V_{n+1} = \frac{W_{n}G_{n} \; + \; \sum_{k=1}^{n-1} W_{k} G_{k}}{\sum_{k=1}^{n} W_{k}} \; \tag{2}$
Then, from the definition of $V_n$, $V_{n} = \frac{\sum_{k=1}^{n-1} W_{k} G_{k}}{\sum_{k=1}^{n-1} W_{k}}$, we have:
$\sum_{k=1}^{n-1} W_{k} G_{k} = V_{n}*\sum_{k=1}^{n-1} W_{k} \; \tag{3}$
Then, substituting $(3)$ in the numerator of $(2)$, we get:
$V_{n+1} = \frac{W_{n}G_{n} \; + \; V_{n}*\sum_{k=1}^{n-1} W_{k}}{\sum_{k=1}^{n} W_{k}} \; \tag{4}$
Then, adding and subtracting $V_{n}W_{n}$ in the numerator of $(4)$, we obtain:
$V_{n+1} = \frac{W_{n}G_{n} \; + \; V_{n}*\sum_{k=1}^{n-1} W_{k} \; + \; V_n W_n \; - \; V_n W_n}{\sum_{k=1}^{n} W_{k}} \; \tag{5}$
We factor $V_n$ in the numerator of $(5)$:
$V_{n+1} = \frac{W_{n}G_{n} \; + \; V_{n}(W_n \; + \; \sum_{k=1}^{n-1} W_{k}) \; - \; V_n W_n}{\sum_{k=1}^{n} W_{k}} \; \tag{6}$
We simplify, taking into account that the denominator $\sum_{k=1}^{n} W_{k} = W_n + \sum_{k=1}^{n-1} W_{k}$, we get:
$V_{n+1} = V_n + \frac{W_n G_n - W_n V_n}{\sum_{k=1}^{n} W_{k}} \; \tag{7} $
Further rearrangements of the terms give us:
$V_{n+1} = V_n + \frac{W_n}{\sum_{k=1}^{n} W_{k}}[G_n - V_n] \; \tag{8}$
Finally, by definition of $C_n$ as the cumulative sum of the weights up to time $n$, we get the desired incremental update equation:
$V_{n+1} = V_n + \frac{W_n}{C_n}[G_n - V_n] \; \tag{9}$