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Proof of gradient of $v_{\pi}(s)$ via Kronecker Product

For the question mark, \begin{align} \sum_{a\in A}\pi(a\mid s,\theta)\sum_{s'\in S}p(s'\mid s,a)\nabla_{\theta}v_{\pi}(s'))&=\sum_{s'\in S}\left(\sum_{a\in A} p(s'\mid s,a)\pi(a\mid s,\theta)\...
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