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May 2, 2020 at 3:57 comment added VIJAY Can you please tell me, in this expression $\frac{\partial}{\partial W^{x}} W^{x}X^{2} = (X^{2})^T$, why have you taken transpose of $(X^2)^T$ as derivative. Why is it not only $(X^2)$
May 1, 2020 at 19:29 comment added user3862410 So, what if we have 3 nodes in the hidden layers (i.e., $H^1$ and $H^2$ should be 3x1 vector) and 2-dimensional inputs ($X^1$ and $X^2$) then $W^h$ is a 3x3 weight matrix and $X^1$ is a 2x1 vector, How can we multiply $(W^h)^T$ and $(X^1)^T$?
May 1, 2020 at 10:30 review First posts
May 3, 2020 at 22:22
May 1, 2020 at 10:26 history answered VIJAY CC BY-SA 4.0